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Download : R A DeCarlo and P Lin Linear circuit analysis solution manuel.pdf





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[원서] R. A. DeCarlo and P. Lin - Linear circuit analysis - solution manuel , [원서] R. A. DeCarlo and P. Lin - Linear circuit analysis - solution manuel공업수학솔루션 , 솔루션

R%20A%20DeCarlo%20and%20P%20Lin%20%20Linear%20circuit%20analysis%20%20solution%20manuel_pdf_01.gif R%20A%20DeCarlo%20and%20P%20Lin%20%20Linear%20circuit%20analysis%20%20solution%20manuel_pdf_02.gif R%20A%20DeCarlo%20and%20P%20Lin%20%20Linear%20circuit%20analysis%20%20solution%20manuel_pdf_03.gif R%20A%20DeCarlo%20and%20P%20Lin%20%20Linear%20circuit%20analysis%20%20solution%20manuel_pdf_04.gif R%20A%20DeCarlo%20and%20P%20Lin%20%20Linear%20circuit%20analysis%20%20solution%20manuel_pdf_05.gif R%20A%20DeCarlo%20and%20P%20Lin%20%20Linear%20circuit%20analysis%20%20solution%20manuel_pdf_06.gif



PROBLEM SOLUTIONS CHAPTER 1.
Solution 1.1. (a) Charge on one electron: -1.6019×10-19 C. This means that charge on 1013 electrons is: -1.6019×10-6 C. Net charge on sphere is: 1.6019×10-6 C (POSITIVE). Solution 1.2. (a) 1 atom ≡ -4.646×10-18 C. By proportionality, 64g ≡ NA atoms . 3.1NA 3.1g ≡ atoms ⇒ 3.1g ≡ atoms . 64 Total Charge = 4.646 × 10 18 C 3.1× 6.023 × 10 23 × atoms = 1.3554 × 10 5 C atom 64

(b) Total charge per atom is -4.646×10-18 C. Total charge per electron is 1.6019×10-19 C. T

PROBLEM SOLUTIONS CHAPTER 1.
Solution 1.1. (a) Charge on one electron: -1.6xxx×10-19 C. This means that charge on 1013 electrons is: -1.6xxx×10-6 C. Net charge on sphere is: 1.6xxx×10-6 C (POSITIVE). Solution 1.2. (a) 1 atom ≡ -4.646×10-18 C. By proportionality, 64g ≡ NA atoms . 3.1NA 3.1g ≡ atoms ⇒ 3.1g ≡ atoms . 64 Total Charge = 4.646 × 10 18 …(생략(省略))



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[원서] R. A. DeCarlo and P. Lin - Linear circuit analysis - solution manuel
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[원서] R. A. DeCarlo and P. Lin - Linear circuit analysis - solution manuel

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